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On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0

2 years ago

What is the solution for the system of equations? Use the elimination method to solve. 2x+y=20 -5y=-6x+12

egoroff_w [7]

Given Equations :

✿ 2x + y = 20 ------------------ [1]

✿ 6x - 5y = 12 ----------------- [2]

Multiplying Equation [1] with 5, We get :

⇒ 5(2x + y) = 5(20)

⇒ 10x + 5y = 100 -------------- [3]

Adding Equations [2] and [3], We get :

⇒ (10x + 5y) + (6x - 5y) = 100 + 12

⇒ 16x = 112

⇒ x = 7

Substituting x = 7 in Equation [1], We get :

⇒ 2(7) + y = 20

⇒ 14 + y = 20

⇒ y = 20 - 14

⇒ y = 7

So, The Solution for the Given System of Equations is : (x , y) = (7 , 7)

3 0

2 years ago

I need to know how to do number 20

zimovet [89]

$(x^4y^3)^2=(x^4)^2(y^3)^2=x^{4\cdot2}y^{3\cdot2}=x^8y^6\\\\Used:\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{n\cdot m}$

6 0

2 years ago

Frank weighs 160 pounds and is on a diet to gain two pounds a week so that he can make the football team. John weighs 208 pounds

gladu [14]

Answer: If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.

Step-by-step explanation:

Let x = Number of weeks.

As per given question ,

Weight of Frank after x weeks = 160+2x (pounds)

Weight of John after x weeks = 208-3x (pounds)

When Weight of Frank= Weight of John

$\Rightarrow\ 160+2x= 208-3x$

$\Rightarrow\ 2x+3x= 208-160$

$\Rightarrow\ 5x= 48\Rightarrow\ x=\dfrac{48}{5}=9.6$

Weight of Frank after 9.6 weeks = 160+2(9.6) = 179.2 pounds

Weight of John after 9.6 weeks = 208-3(9.6)=179.2 pounds

Hence, If Frank and John can meet these goals with their diets , they will weigh same after 9.6 weeks and they will weigh 179.2 pounds.

3 0

2 years ago

9

saw5 [17]

The value of the expression, g/2 + 3 when x = 8 is: 7.

<h3>How to Evaluate an Expression?</h3>

Given the expression, g/2+3, to find it's value when g = 8, plug in the value of g into the expression and solve.

g/2 + 3

8/2 + 3

Divide

4 + 3

= 7

The value of the expression is: 7.

Learn more about evaluating an expression on:

brainly.com/question/4009675

#SPJ1

4 0

1 year ago