Answer: The answer is 139 feet
H = height of the pole =?
BC = ED = height of the transit = 4 ft
CD = BE = distance moved away from the base of the pole = 140 ft
Consider the ΔABE
tan44 = AE/BE
tan44 = h/140
h = 140 tan44
h = 135.2 ft
H = height of pole = AE + ED = h + ED = 135.2 + 4
H = 139.2 ft
Step-by-step explanation:
a. The marginal densities

and

b. This can be obtained by integrating the joint density over [0.25, 1] x [0.5, 1]:

90,000 becuase 63,824 is rounded down to 60,000 and 29,452 is rounded up to 30,000. 60,000+30,000 is 90,000
The answer is (C) because you multiply each point by 1.5.
Answer:
The wire is approximately 42feet long
Step-by-step explanation:
We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.
The hypotenuse side is the length of the wire we are looking for.
Parameters are given as:
Opposite : 30ft
Adjacent: 30ft
Hypotenuse: x feet
The hypotenuse = 
Hypotenuse =