Number 8 is C. I'm still trying to figure out what number 7 is.
Answer:
x = 2
y = -1
Step-by-step explanation:
2x + y = 3
-2y = 14 - 6x
6x - 2y = 14
2x + y = 3 | ×3 |
6x - 2y = 14 | ×1 |
6x + 3y = 9
6x - 2y = 14
__________--
5y = -5
y = -5/5
y = -1
2x + y = 3
2x + (-1) = 3
2x = 3 + 1
2x = 4
x = 4/2
x = 2
Answer:
x=8
base side of isosceles triangle
y=√{8²+8²}=8√2
Answer:
Hi there, you can use Pitagoras relationship to solve this up (Without using any other "tool".
Point A is located wheter in (-6,8) or could be located in (-6,8)
Step-by-step explanation:
Point A is 10 units away from the origin, and its x coordinate is -6, using this information, you can draw a triangle from 0 to -6 (the basis) and using 10 as the hypotenuse, so, you have this equation:
solving for Y variable, you have this
y=±
Note the combined sing ±, meaning that y=8 is a valid answer and that y= -8 is also a valid answer.
Hope It helps
1. 8 = 8 => refrexive
2. If x = y, then y = x => symmetric
3. If x = y and y = 7, then x = 7 => transitive
4. 6 + 2 = 2 + 6 => commutative - addition
5. 5 ∙ 2 = 2 ∙ 5 => commutative - multiplication
6. 10 + (3 + 2) = (10 + 3) + 2 => associative - addition
7. 6(3 ∙ 5) = (6 ∙ 3)5 => associative - multiplication
8. 4(8 + 1) = 4 ∙ 8 + 4 ∙ 1 => distributive
9. 6 + 0 = 6 => identity - addition
10. 8 ∙ 1 = 8 => identity - multiplication
11. 1/2 ∙ 2 = 1 => multiplicative inverse
12. 5 ∙ 0 = 0 => property of zero
