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Ilia_Sergeevich [38]
3 years ago
5

The complex ion [CoBr6]3− is a high-spin complex and absorbs light at a wavelength greater than 7.70×102 nm . How many unpaired

electrons will be present in the complex?
Mathematics
1 answer:
NeX [460]3 years ago
3 0

Answer:

4 electrons

Step-by-step explanation:

[CoBr₆]³⁻ contains Cobalt as the central metal ion and 6 bromide atoms are bonded to the metal as ligands.

Bromide is a weak field ligand and thus pairing of the electrons will not take place and the complex, [CoBr₆]³⁻ is a high spin complex.

The oxidation number of Co in [CoBr₆]³⁻ is +3.

The Electronic configuration of Co³⁺ in [CoBr₆]³⁻ (d⁶) in a weak field octahedral environment is t_{2g}^4 e_g^2

<u>Number of unpaired electrons = 4 electrons</u>

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During a dig, an archaeological team starts at an elevation of −512 feet. At a rate of 234 feet per hour, the team digs deeper i
creativ13 [48]
Are you referring to this question?
During a dig, an archaeological team starts at an elevation of −5 1/2 feet. At a rate of 2 3/4 feet per hour, the team digs deeper into the surface for 3 1/2 hours. For the next 4 1/2 hours, the team digs at a rate of 1 5/12 feet per hour. Then the team quits for the day.
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</span>
If so, then let us find out the elevation.

The rate of their dig is 2 3/4 ft per hr for 3 1/2 hours, then the total distance dug after 3 1/2 hours should be: 9 5/8 ft

Here’s how we get the total distance:

 First, change mixed number into improper fraction and proceed to multiplication

2 3/4--> 11/4  and  3 1/2  becomes 7/2

Multiply.

11/4  x  7/2  = 77/8

Simplify 77/8--> 9 5/8 ft

 

Let us move on at the rate of 1 5/12 ft per hr for the next 4 1/2 hr,

Following the same procedure as above, the distance would be: 6 9/24 ft

 

Distance= 1 5/12 x 4 1/2

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       = 153/24

       = 6 9/24 ft

 

Thus,to sum up everything, they have a total dug of:

 9 5/8 + 6 9/24 = 9 15/24 + 6 9/24 = 16 ft

 

Then, their elevation on that day<span> is -5 1/2 - 16 = -21 1/2 ft</span>

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4 years ago
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