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andreyandreev [35.5K]
3 years ago
14

Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule

, answer the following questions: a) What is the approximate percentage of men between 169 and 183 cm? b) Between which 2 heights would 95% of men fall? c) Is it unusual for a man to be more than 197 cm tall? Explain.
Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

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Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

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4 0
1 year ago
Leon started to try to transform the expressions 6g + (g + 2) + 3 to determine if it is equivalent to the expression 6 + 7g. His
hodyreva [135]
By using the associative property [(5*3)*12] is equal to
[5*(3*12)] .
Option (A) is correct .
Step-by-step explanation:
Definition of associative property of multiplication
Let us assume that x , y and z be the three real numbers .
x × (y × z ) = (x × y) × z
This is called the associative property .
As given the expression be as follow
= [(5*3)*12]
Here
x = 5 , y = 3 , z = 12
By using the associative property
[(5*3)*12] = [5*(3*12)]
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Read more on Brainly.com - brainly.com/question/3604873#readmore
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Hope this helps!

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for what value of k, the line joining 3x-ky+7=0 is perpendicular to the line joining (4 ,3) and ( 5, -3).
Schach [20]

Answer:

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=========

<h2>Given</h2>

<h3>Line 1</h3>
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<h3>Line 2</h3>
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<h2>To find</h2>

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<h2>Solution</h2>

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Find the slope of line 1 by converting the equation into slope-intercept from standard form:

<u><em>Info:</em></u>

  • <em>standard form is ⇒ ax + by + c = 0, </em>
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Its slope is 3/k.

Find the slope of line 2, using the slope formula:

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