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Gelneren [198K]

3 years ago

5

A basket has 12 white eggs and 4 brown eggs. Half of the white eggs are cracked, what is the probability I will chose a white cr

acked egg

1 answer:

Pachacha [2.7K]3 years ago

3 0

37.5 percent chance.

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This graph shows a system of equations what is the solution to the system of equations 1.(-2,2) 2.(2,2) 3.(2,-2) 4.(-2,-2)

Nutka1998 [239]

Answer:

I honestly don't know that fashoo

5 0

2 years ago

Find The value of X to the nearest tenth<br> A 7.0<br> B 4.7<br> C 5.7<br> D 8.2

vredina [299]

Here is the correct answer, and explanation for how to get the answer, and a way to remember how to use them for next time :)

3 0

3 years ago

The polynomial equation x5-16x2=4x4-64 has complex roots + or - 2i what are the other roots? use a graphing calculator and a sys

hichkok12 [17]

Kindly proofread the question!!!

The leading term is x^6, not x5.

Answer: The additional roots are -2, +2, each with multiplicity 2.

Step-by-step explanation:

x^6 - 16x^2 = 4x^4 - 64

x^6 - 4x^4 - 16x^2 + 64 = 0

(x+2i)(x-2i) = (x^2+4) is a factor.

(x-2)(x+2)(x-2)(x+2)(x^2+4) = 0

Polynomial long division by x^2+4

x^6 - 4x^4 - 16x^2 + 64 = 0

First term of quotient is x^4

Subtract x^6+4x^4

Remainder is -8x^4 -16x^2+64

Second quotient term is -8x^2

Subtract -8x^4-32x^2

Remainder is 16x^2+64

Third quotient term is 16

Subtract 16x^2+64

Remainder is zero

Quotient is x^4 - 8x^2 + 16

(x^2-4)^2 = x^4 + 2(1)(-4)x^2 + 16

(x-2)(x+2)(x-2)(x+2)(x^2+4) = 0

4 0

3 years ago

What is the relationship between rigid motions and congruence?

r-ruslan [8.4K]

Answer:

Rigid Motion and Congruence Two figures are congruent if and only if there exists one, or more, rigid motions which will map one figure onto the other. (thus maintaining the conditions for the figures to be congruent).

Step-by-step explanation:

7 0

3 years ago

In ℝ2, you are given the points A(−14,15) and X(13,−17). Find t such that the point C(−12,t) lies on the line through A and X. a

Lostsunrise [7]

Answer:

The equation of the line segment between points A and X is

$sA + (1-s)X, s\in[0,1]$

Then we need that the point C satisfy:

$\left[\begin{array}{c}-12\\t\end{array}\right] =\left[\begin{array}{c}-14s\\15s\end{array}\right]+\left[\begin{array}{c}13(1-s)\\-17(1-s)\end{array}\right]$ .

This implies that

$-12=-14s-13s+13\\s=\frac{25}{27}$

We replace the value of s in the equation we get from the second component

$t=15s+17s-17\\t=32\frac{25}{27}-17\\t=\frac{341}{27}$

Then the point $C=(-12,\frac{341}{27})$ lies on the line through A and X.

8 0

2 years ago