PLEASE ANSWER THIS AS SOON AS POSSIBLE.

How many times greater is 1 kilogram than 1 microgram?

Pani-rosa [81]

Using this table as a reference, you can see the following: A kilogram is 1,000 timeslarger than one gram (so 1 kilogram = 1,000 grams). A centimeter is 100 timessmaller than one meter (so 1 meter = 100 centimeters). A dekaliter is 10 timeslarger than one liter (so 1 dekaliter = 10 liters).

7 0

3 years ago

Read 2 more answers

What is the formula that relates circumference and radius?

cestrela7 [59]

B is the correct answer choice I know it

6 0

3 years ago

Plzzz guys, help me with this

babunello [35]

Answer:

Distributive property

Step-by-step explanation:

-3/4*5/4-(-6/7)*(-3/4)

-15/16-(18/28)

-15*7-18*4/112

-105-72/112

-177/112

4 0

3 years ago

Read 2 more answers

1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago

A random sample of 160 car crashes are selected and categorized by age. The results are listed below. The age distribution of dr

sasho [114]

Answer:

25.05

Step-by-step explanation:

Given that a random sample of 160 car crashes are selected and categorized by age. The results are listed below. The age distribution of drivers for the given categories is 18% for the under 26 group, 39% for the 26-45 group, 31% for the 45-65 group, and 12% for the group over 65.

<26 26-45 46-65` >65

Observed O 66 39 25 30 160

Expected E 40 40 40 40 160

Chi square

(O-E)^2/E 16.9 0.025 5.625 2.5 25.05

Thus we get chi square test statistic = 25.05

5 0

3 years ago