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3 years ago

Find the difference 701 and 413

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

7 0

Answer:

I believe its 288 I might be wrong but it's worth a shot

You might be interested in

I will give branniest

KonstantinChe [14]

Answer:

112.5

Step-by-step explanation:

24x=2700

=> x= 2700/24

= 112.5

Therefore, x= 112.5

8 0

2 years ago

Which expression can be used to find the volume of the sphere?

Kryger [21]

Answer:

They used 3.14 for pi:

$V=\frac{4}{3} \pi r^3$

$V=\frac{4}{3} (3.14)(5)^3$

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3$ is the volume of a sphere with radius r.

I think that is the diameter given in the picture.

The radius is half the diameter.

So the radius is 5 since the diameter is 10.

Plug in this gives you:

$V=\frac{4}{3} \pi (5)^3$

4 0

3 years ago

Read 2 more answers

8. Find the area of the shaded region.

Solnce55 [7]

Answer:

Step-by-step explanation:

did the math

6 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

3 years ago

Just number 14. Nothing other unless u want to

Shkiper50 [21]

Answer: 4 parfaits.

Step-by-step explanation: 1/2 divided by 1/8. when you divide you flip the second fraction and multiply it so now it's 1/2 x 8/1 which is 8/2 and then is turned into 4 so 4 parfaits

Hope this helps im really good at fractions if you need anything else lol :')

6 0

4 years ago