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Andrew [12]
3 years ago
9

What is the solution to the system of equations?

Mathematics
2 answers:
Goryan [66]3 years ago
6 0
(-3,2) is the correct answer
PIT_PIT [208]3 years ago
3 0
(-3,2)

Explanation: put the numbers into the equations. -3 is x and 2 is y.
-2(-3) + 2 = 8
-3(-3) - 2 = 7
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True or false f (x) is a function
adoni [48]

Hello from MrBillDoesMath!

Answer:

True

Discussion:

From the diagram, f maps each x to a unique value so f is a function. One such possible possible function (but not the only one!) that does this is


f(x) =  x/4


Thank you,

MrB

5 0
3 years ago
Read 2 more answers
Solve: negative 1 over 2 x + 2 = −x + 7<br><br> 10<br><br> 5 over 2<br><br> 2 over 5<br><br> 20
yan [13]
-1/2x + 2 = -x + 7
-1/2x + x = 7 - 2
1/2x = 5
x = 10
7 0
3 years ago
Read 2 more answers
The number of times that students go to the movies per year has mean is a normal distribution with a mean of 17 with standard de
antiseptic1488 [7]

Answer:

53.84% probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a sample of size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 17, \sigma = 8, n = 10, s = \frac{8}{\sqrt{10}} = 2.53

What is the probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times?

This probability is the pvalue of Z when X = 18 subtracted by the pvalue of Z when X = 14. So

X = 18

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{18 - 17}{2.53}

Z = 0.4

Z = 0.4 has a pvalue of 0.6554

X = 14

Z = \frac{X - \mu}{s}

Z = \frac{14 - 17}{2.53}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170

0.6554 - 0.1170 = 0.5384

53.84% probability that for a group of 10 students, the mean number of times they go to the movies each year is between 14 and 18 times.

3 0
3 years ago
What is 7/8 times 6/8
n200080 [17]

Answer:

\frac{21}{32}

Step-by-step explanation:

When multiplying fractions, you multiply the numerators together and denominators together. This means that the problem above can be rewritten as, \frac{7*6}{8*8}. Then, multiply this out to get \frac{42}{64}. However, this fraction can be simplified by dividing the numerator and denominator by 2. This gives the final answer, \frac{21}{32}.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!! ASAP I don't understand this!!!
Paladinen [302]

Answer by JKismyhusbandbae: So this is really simple. You are probably making this out harder than it needs to be. Consider the set of ordered pairs {(-1,0), (4,-5), (6,-6), (9,11), (10,14)}.  This set of ordered pairs is a function because for each value of x there is one and only one y-value.  This means that the x value never repeats.  Therefore any function is a function when the x value never repeats.

Looking at the table we want to find all it's ordered pairs: (0,4), (1,2), (2,3), (3,9), (4,1).

F(2) is 3 so when x equals 2.

So the ordered pair is (2,3) 2 is the x value and the f(2) is 3.

7 0
4 years ago
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