2 years ago

A rectangle is 12cm long and 5cm wide. Find the size of the angle marked x.

Mathematics

1 answer:

neonofarm [45]2 years ago

4 0

Answer:

22.61°

Step-by-step explanation:

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Right the slope intercept form of the equation of of each line

Burka [1]

Answer:

Slope intercept form is y=mx+b

So y=-1/2x(m=slope which you go down one over 2 from your y-intercept)

y=-1/2x ( There would be no b because your b is 0, that's where it crosses the y axis)

Step-by-step explanation:

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3 years ago

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Radda [10]

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Step-by-step explanation:

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3 years ago

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lapo4ka [179]

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3 years ago

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Vilka [71]

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3 years ago

Find the derivative of the function at P 0 in the direction of A. f(x,y,z) = 3 e^x cos(yz), P0 (0, 0, 0), A = - i + 2 j + 3k

Alik [6]

The derivative of $f(x,y,z)$ at a point $p_0=(x_0,y_0,z_0)$ in the direction of a vector $\vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k$ is

$\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}$

We have

$f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k$

and

$\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}$

Then the derivative at $p_0$ in the direction of $\vec a$ is

$3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}$

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3 years ago