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Dvinal [7]
2 years ago
14

Help help help help help help

Mathematics
2 answers:
denis-greek [22]2 years ago
6 0

Step-by-step explanation:

{6}^{2}  \div  {6 }^{2}  =  {6}^{7 - 2}   =  {6}^{5}

hope it helps.

stay safe healthy and happy.

kati45 [8]2 years ago
4 0

Answer:

6^{5}

Step-by-step explanation:

I hope this helps

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I need to find the surface area for this one pls help me
Alex

Step-by-step explanation:

so, you got the volume but don't know how to find the surface area ? that is strange for me. what's the problem ?

the surface of a cube or rectangular prism consists of 6 sides that split (for a rectangular prism) into 3 pairs of equal sides :

top and bottom

left and right

front and back

all we need to do is calculate the areas of these 6 rectangles and add them up. that's it.

in our case

top and bottom : 5×4 × 2 = 20×2 = 40 in²

left and right : 4×4 × 2 = 16×2 = 32 in²

front and back : 5×4 × 2 = 40 in²

so, in total, the whole surface area of the prism is

40 + 32 + 40 = 112 in²

4 0
2 years ago
13. Which of the following is the graph of y = 3(1⁄5)x?
Fittoniya [83]

Answer:

Second graph

Step-by-step explanation:

The second graph is the correct one.  Why?  because the y intercept is (0, 3), and also because the base, 1/5, is between 0 and 1, which leads to a decaying exponential graph.

6 0
3 years ago
Evaluate the expression (6 + 9 ÷ 3) × 7.
Katarina [22]

Answer:

63

Step-by-step explanation:

(6+9÷3)×7

division is always first

(6+3)×7

then parenthesis

9×7

multiply

63

3 0
3 years ago
Read 2 more answers
What is 27cm added to 1m 80cm
nikdorinn [45]
1cm means 1 centimeter
centi=1000 so
1cm=1/1000m
1m=1000cm

so 27cm+1m+80cm=27cm+1000cm+80cm=1107cm=1.107m
5 0
3 years ago
Read 2 more answers
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
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