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2 years ago

Help help help help help help

Mathematics

2 answers:

denis-greek [22]2 years ago

6 0

Step-by-step explanation:

${6}^{2} \div {6 }^{2} = {6}^{7 - 2} = {6}^{5}$

hope it helps.

stay safe healthy and happy.

kati45 [8]2 years ago

4 0

Answer:

$6^{5}$

Step-by-step explanation:

I hope this helps

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Calculate the area of a circle with a dime tier of 16cm pi=3

Mashcka [7]

The area of every circle is (pi) (radius²) .

Radius = 1/2 of the diameter, so the area of your circle is

(pi) x (8 cm)² = 201 cm² . (rounded)

(pi) is not 3 . There's nothing wrong with approximating (pi),
but 3 is more than 4.5% wrong, and that's too much. There's
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2 years ago

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How do you solve and simplify 2/5+1/4+7/10=

Alchen [17]

Hello!

Answer: ⇒ 27/20

Step-by-step explanation:

$\frac{8}{20}+\frac{5}{20}+\frac{14}{20}$

Since the denominators are equal, then combine the fractions.

$\frac{8+5+14}{20}$

Add by the numbers.

$8+5+14=27$

$=\frac{27}{20}$

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The table shows the gallons of water in a pool over time.

Valentin [98]

Answer:

6 gallons per minute

Step-by-step explanation:

Let the function that models the quantities of water, Q (in gallons) in a pool over time, t (in minutes), is

Q = a + bt ........... (1)

Now, Q(t = 0) is given to be 50 gallons.

So, a = 50 and b denotes the rate at which the quantity of water in the pool is decreasing and it is given by the slope of equation (1).

Now, two points on the graph are (0,50) and (1,44).

So, the slope = b = = - 6 gallons per minute.

Therefore, the equation of this situation is given by Q = 50 - 6t, where the slope is equal to - 6 gallons per minute. (Answer)

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If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?

Alisiya [41]

If $k$ is odd, then

$\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor$

while if $k$ is even, then the sum would be

$\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4$

The latter case is easier to solve:

$\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0$

which means $k=6$ .

In the odd case, instead of considering the above equation we can consider the partial sums. If $k$ is odd, then the sum of the even integers between 1 and $k$ would be

$S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)$

Now consider the partial sum up to the second-to-last term,

$S^*=2+4+6+\cdots+(k-5)+(k-3)$

Subtracting this from the previous partial sum, we have

$S-S^*=k-1$

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$S=2k$
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jose has $12.80 in nickels and dimes. there are a total of 144 coins. how many nickels and dimes are there

Nastasia [14]

There are 32 nickels and 112 dimes. Hope this helps.

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