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Vedmedyk [2.9K]
2 years ago
11

Find the domain and range of the function f(x) = 5x – 41 + 3

Mathematics
1 answer:
Strike441 [17]2 years ago
4 0

Answer: is it for math

Step-by-step explanation:

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The output is a ratio of sides of a triangle.
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3 years ago
The area of<br>of a rectangle is (14x^4 + 7x^2) cm²<br>and its breadth is 7x^2 cm. Find its length.​
NeTakaya

Answer:

2x^1+1

Step-by-step explanation:

Area=L X W

which means that (14x^4+7x^2) needs to be divided by 7x^2

factorise(14x^4+7x^2) which gives 7x(2x^2+1)

divide 7x(2x^2+1) by 7x^2

gives 2x^2 +1

7 0
2 years ago
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Can anyone help solve this equation?
koban [17]

Answer:

13

Step-by-step explanation:

3 x 3 = 9

7 + 3 = 10

7 + ? = 3 + 7 + 3 + 7

7 + ? = 20

? = 13

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3 years ago
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Use the drawing tool(s) to form the correct answer on the provided number line. Consider the given functions. Function 1 Functio
Anna007 [38]

Both functions decrease at (-1, 2)

<h3>How to determine the decreasing intervals of the function?</h3>

The complete question is added as an attachment

The polynomial function f(x) is represented by the graph.

From the graph, the polynomial function decreases at (-2, 2)

The absolute function is given as;

f(x) = =5|x + 1| + 10

The vertex of the above function is

Vertex = (-1, 10)

Because a is negative (a= -5), the vertex is a maximum.

This means that the function decreases at (-1, ∞)

So, we have

(-2, 2) and (-1, ∞)

Combine both intervals

(-1, 2)

This means that both functions decrease at (-1, 2)

See attachment 2 for the number line that represents the interval where both functions are decreasing

Read more about function intervals at:

brainly.com/question/27831985

#SPJ1

3 0
1 year ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
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