see the attached figure to better understand the problem
we know that
The Area of the composite figure is equal to the sum of Area 1, Area 2 and Area 3
The Area 1 is a triangle
The Area 2 is a rectangle
The Area 3 is equal a semicircle
therefore
<u>the answer is the option</u>
a triangle, a rectangle, and a semicircle
Answer:
The distance between the hands is √(3)cm ≈ 1.73cm.
Step-by-step explanation:
In a standard clock, the angle between every number is 30°, therefore the angle between 12 and 2 will be 30° x 2 = 60°.
Looking at the diagram, to find c we can make use of our cosine formula
c² = a² + b² –2abCos(C°)
a = 2, b = 1 and C° = 60°
Therefore we have:
c² = 2² + 1² –2 x 2 x 1 x cos(60°) =
c² = 4 + 1 – 4 x 0.5 =
c² = 5 – 2 =
c² = 3
c = √(3) ≈ 1.73
Therefore, the distance between the hands is √(3)cm ≈ 1.73cm.
