The answer to the question
<span>We already know that angles ECS and TRS are congruent, because they are both right angles (given). We also know that angles CSE and RST are congruent because they are vertical angles and vertical angles are always congruent. That gives us two sets of congruent angles. We just need to know something about one pair of sides to prove the two triangles congruent to each other. I do question the order of the letters in the names of the triangles--if that's really the order the letters are written in the problem, then we would need to know that ES is congruent to RT or that CS is congruent to ST. If the order of the letters of the names of the triangles is a little different we would need to know that CS is congruent to RS or that any of the other sides that appear to match are actually congruent. </span>
Answer:
62.8 meters
Step-by-step explanation:
circumference of A = 50π meters
circumference of B = 70π meters
difference = 70π - 50π = 20π meters ≅ 62.8 meters
WE need to find the probability (
We know 
P()=
First we find P(Boy)
From the table we can see that we have 12 boys out of (12+18=30) students
So P(Boy) = 
Now we find the intersection of Junior and Boy
WE look at the Junior row and boys column that is 2
{P(Junior ∩ Boy) = 
P()=
P()= 
= 
= 
P() =
Answer:
y= -3 + 2x
Step-by-step explanation:
