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2 years ago

Calculate 2.43 x 4 = (full working required

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

5 0

Answer: 9.72

To make it easier you first remove( imagine)there is no decimal point. Then u multiply the number which is 4 through all the digits to get 972.

But u are not done yet because u have forgotten the decimal point. To know where to put the decimal point u have to count the number of places it was in order to know where to place it.

So it was 2 decimal places,so we count it and place it there to get 9.72

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Math question

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

2 years ago

What is the end behavior? 10 points!!

Colt1911 [192]

Given:

The given function is:

$f_1(x)=-3\cdot 2^{x-5}-4$

The graph of the function is given.

To find:

The end behavior of the given function.

Solution:

We have,

$f_1(x)=-3\cdot 2^{x-5}-4$

From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.

$f_1(x)\to -4$ as $x\to -\infty$

$f_1(x)\to -\infty$ as $x\to \infty$

Therefore, the end behaviors of the given function are:

$f_1(x)\to -4$ as $x\to -\infty$

$f_1(x)\to -\infty$ as $x\to \infty$

4 0

2 years ago

PLS ANSWER WILL GIVE BRAINLIEST TO PERSON WHO ANSWERS WITHIN 5 MINUTES

hoa [83]

Answer:

49.73

Step-by-step explanation:

You make the fractions into decimals and get 9.5 and 7.3. Then multiply those by the price given to get $23.75 and 25.98. When you add those numbers together you get $49.73.

7 0

3 years ago

Read 2 more answers

A middle school campus is shaped like a rectangle with a width of 1/4 mile and a length of 1/2 mile. A map of the campus has a w

igomit [66]

Answer:

A) 1:4

Step-by-step explanation:

#We first calculate the campus' area:

$a=lw\\\\=\frac{1}{4}\times \frac{1}{2}\\=0.125 \ mi^2$

#We then calculate the campus' map area in square ft:

$A=lw\\\\=0.5 \times 1\\\\=0.5 ft^2$

Ratio is a comparison between two dimensions:

$Ratio=\frac{0.125}{0.5}\\\\=0.25\\\\=\frac{1}{4}\\\\=1:4$

Hence, the ratio of the area in square miles of the campus to the area in square feet of the map is 1:4

3 0

2 years ago

Given the piecewise function shown below, select all of the statments that are true.

timurjin [86]

The given the piecewise function is :

$f(x) = \[ \begin{cases} 
 2x & x \ \textless \ 1 \\
 5 & x=1 \\
 x^2 & x\ \textgreater \ 1 
 \end{cases}
\]$

To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25

To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4

To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4

To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
================================
So, the statements which are true:
$\framebox {B. f(2) = 4} \ \framebox {D. f(1) = 5}$

8 0

3 years ago