Answer:
The maximum distance traveled is 4.73 meters in 0.23 seconds.
Step-by-step explanation:
We have that the distance traveled with respect to time is given by the function,
.
Now, differentiating this function with respect to time 't', we get,
d'(t)=9.8t-2.3
Equating d'(t) by 0 gives,
9.8t - 2.3 = 0
i.e. 9.8t = 2.3
i.e. t = 0.23 seconds
Substitute this value in d'(t) gives,
d'(t) = 9.8 × 0.23 - 2.3
d'(t) = 2.254 - 2.3
d'(t) = -0.046.
As, d'(t) < 0, we get that the function has the maximum value at t = 0.23 seconds.
Thus, the maximum distance the skateboard can travel is given by,
.
i.e. 
.
i.e. 
.
i.e. .
i.e. d(t) = 4.73021
Hence, the maximum distance traveled is 4.73 meters in 0.23 seconds.
Answer:
Step-by-step explanation:
(-3x + 2)(45x + 21) + (-4x + 25) = 50
-135x^2 - 63x + 90x + 42 - 4x + 25 = 50
-135x^2 + 23x + 67 = 50
-135x^2 + 23x + 67 - 50 = 0
-135x^2 + 23x + 17 = 0
quadratic formula : x = (-b ± √b^2 - 4ac)/2a
a = -135, b = 23, c = 17
x = -23 ± √23^2 - 4(-135)(17) / (2(-135)
x = (-23 ±√9709 )/ -270
x = 23/270 ± 1 / 270√9709/270
x = 0.4501 or x = - 0.2798 <=== these answers are rounded
<span>one billion twenty-four million</span>
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
Answer:
6(3+7)
Step-by-step explanation:
i believe that is correct
