1. h(x) = 3
Let f(x) = 3x and g(x) =
2. N(x) = (
)⁵
Let f(x) = x⁵ and g(x) = 2x and h(x) = 
Answer:
9,11
Step-by-step explanation:
let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)
therefore;
x(x+2)= 99
x²+2x=99
I usually solve the sum like this,
we need to find the nearest square number ( number smaller than the number on the R.H.S)
here, it is 81, whose square root is 9. therefore the solution is 9
verification:
(9)²+2*9=99
81+18=99
99=99
hence, 9 is the solution. therefore the positive odd consecutive integers are
x=9
x+2=9+2= 11
verification:
9*11=99
99=99
L.H.S=R.H.S
Drop the questions it’s blank
Your answer is 1.25
dividing:
Set up the equation. On a piece of paper, write the dividend (number being divided) on the right, under the division symbol, and the divisor (number doing the division) to the left on the outside. ...
Divide the first digit. ...
Divide the first two digits. ...
Enter the first digit of the quotient.
I hope it helps.
F^-1(x)=1+5×2x
I hope this helps
