Question

9 cm

Answer 1

Answer:

∴ ∠BAD = $sin^{-1}$(0.2044) = 11.8°

Step-by-step explanation:

i) AD = 9 cm

ii) DC = 3 cm

iii) ∠BCD = 35°

iv) Since AB is parallel to DC and ∠ABD = 90°  then we can conclude that ∠BDC = 90°.

v) $\frac{BD}{DC} = \frac{BD}{3\hspace{0.1cm}cm} = tan(35)$ = 0.6128      ∴ BD  = 3 $\times$ 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) = $\frac{BD}{AD}$      ⇒     sin(∠ BAD ) = $\frac{1.84}{9}$ = 0.2044

     ∴ ∠BAD = $sin^{-1}$(0.2044) = 11.8°