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Serga [27]
4 years ago
6

9 cm

Mathematics
1 answer:
OLEGan [10]4 years ago
7 0

Answer:

∴ ∠BAD = sin^{-1}(0.2044) = 11.8°

Step-by-step explanation:

i) AD = 9 cm

ii) DC = 3 cm

iii) ∠BCD = 35°

iv) Since AB is parallel to DC and ∠ABD = 90°  then we can conclude that ∠BDC = 90°.

v) \frac{BD}{DC}  =  \frac{BD}{3\hspace{0.1cm}cm}  = tan(35) = 0.6128      ∴ BD  = 3 \times 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) = \frac{BD}{AD}      ⇒     sin(∠ BAD ) = \frac{1.84}{9} = 0.2044

     ∴ ∠BAD = sin^{-1}(0.2044) = 11.8°

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