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Shkiper50 [21]
3 years ago
8

JESUS I DONT GET THIS SOMETIMES, PEOPLE BE LIKE "X=69420" WHEN THE PROBLEM IS IN GRAPH FORM IM SO CONFUSED LIKE IM SORRY THAT WE

ARE NOT GENIUSES CAN YOU AT LEAST GIVE US THE FULL ANSWER LIKE .
Mathematics
1 answer:
puteri [66]3 years ago
4 0

Answer:

Equation: y = -3x -2

Graph: Attached below ↓↓↓↓↓

Step-by-step explanation:

The equation is y = -3x + b

We need B at this point.

Since we have a point given to us,( -2, 4)we can input the x and y

Solve:

4 = -3(-2) + b

4 = 6 + b

b = -2

So the equation we have is y = -3x -2

Let's graph the line.

We go 2 units below the x-axis, because the y-intercept is -2, and the slope is -3, so we go down 3 units, and to the right 1.

Picture attached:

-Chetan K

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WHAT IS THE VOLUME OF WAX IN THE CANDLE SHAPED LIKE A CYLINDER
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Problem 8

<h3>Answer:  28.3 cubic inches</h3>

------------------------

Work Shown:

V = pi*r^2*h

V = 3.14*(1.5)^2*4

V = 28.26

V = 28.3

Note how the radius r = 1.5 is half of the diameter 3 inches.

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Problem 9

<h3>Answer:  25.1 cubic inches</h3>

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V = (1/3)*pi*r^2*h

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Which expression can be used to determine the slope of the linear function represented in the table?
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Calculate the area of the figure below using the following information:
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"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
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Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b) Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c) P(\bar X >31.25)=0.006=0.6\%

d) P(\bar X >28.25)=0.9997=99.97\%

e) P(28.25

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

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