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3 years ago

Factorise: 25x²-20x+4

Mathematics

2 answers:

Nutka1998 [239]3 years ago

4 0

(5x - 2)²

Step-by-step explanation:

25x² - 20 + 4

(5x - 2)(5x - 2)

(5x - 2)²

kogti [31]3 years ago

3 0

Answer: (5x-2)^2

Step-by-step explanation: I just thought of the answer

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G = {(5, 3), (2, 3), (6, 4)} Is G-1 a function and why?

galben [10]

To get G^-1 all we need to do is flip the points around Example for (5,3) make it (3,5)
Here are the points in inverse (3,5); (3,2); (4,6)
To tell if a group of point can be a function we need to 1st look at the x values. If all the x values are different, then it is a function (the x's are not all different)
If there are x values that are the same, they MUST have the same y value.
look at the points (3,5) and (3,2) those have the same x but they go to different y values so it is not a function.

You can think about it like this. Can you go to more than 1 place at the EXACT same time? Obvious answer is no. Can you have multiple people go to the same room? Sure that is possible. Same with functions. An x value can ONLY go to 1 y value, and many different x values can go to the same y value.

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3 years ago

Help please! i appreciate it

BlackZzzverrR [31]

Answer:- 1) there are three terms

2) 3,4,1

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3 years ago

Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o

galina1969 [7]

Answer: The correct options are

(A) relation

(B) function.

Step-by-step explanation: We are given to check whether the following set is a relation or a relation and a function or neither :

A = {(1, 2) (2, 2) (3, 2) (4, 2)} .

Let us consider the following two sets :

U = {1, 2, 3, 4} and V = {2}.

Then, we see that the Cartesian Product of U and V is given by

U × V = {(1, 2) (2, 2) (3, 2) (4, 2)}.

Since a relation is a subset of Cartesian product, so the given set A is a relation.

Also, we know that a relation is a function if every first element is associated with one second element.

Since the relation A satisfies this condition, so the relation A is a function.

Thus, the given set A is both a relation and a function.

Option (A) and (B) are correct.

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3 years ago

On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)

goldfiish [28.3K]

Answer:

f(x) > 0 over the interval $(-\infty,-4)$

Step-by-step explanation:

If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from $- \infty$ , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from $- \infty$ to -3, since between the values -4 and -3 the function adopts negative values.

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3 years ago

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