Let x be a random variable representing the mean weight of a one-year-old Hereford bull. Then
a.) P(x < 1100) = P (z < (X - mean)/sd) = P(z < (1100 - 1150)/80) = P(z < -0.625) = 1 - P(z < 0.625) = 1 - 0.73401 = 0.2660
b.) The middle (50%) of Hereford weights will weigh the mean weight of the sample. i.e. the middle (50%) of the Hereford weights will be 1150 pounds
The prime numbers between 30 and 45 are 31, 37, 41, and 43
87 x 57 = 4959
20000/4959 = 4.033071184
density = 4 fans per yard²
Answer:
The responses to these question can be defined as follows:
Step-by-step explanation:
For point a:

For point b:

