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agasfer [191]
4 years ago
9

fond two consecutive odd integers whose sum is 36 which of the following equations could be used to solve the problem

Mathematics
1 answer:
Travka [436]4 years ago
4 0

Answer:

17 is the answer.

Step-by-step explanation:

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8 0
3 years ago
Please check my answer for 10+3(x+2)=36. I got x=6 2/3 or 6.66666667. I want to make sure I’m right.
White raven [17]

You are right! 6 2/3 is the answer

Step-by-step explanation:

10+3(x+2)=36

10+3x+6=36

16+3x=36

3x= 20

x=6 2/3

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2 years ago
Need help plzzzz will medal and fan
andriy [413]
The answer is f(x)=x²+2x when evaluated with -3 gives you the value of 3

Let's check all functions.
1. The function f(x)=x²<span>+2x when evaluated with 3 gives you the value of 3:
  Evaluated with x means that</span> x = 3.
   f(3) = 3² + 2 * 3 = 9 + 6 = 15 
   15 ≠ 3, so, this is not correct.

2. f(x)=x²<span>-3x when evaulated with -3 give you the value of 3
    Evaluated with -3 means that x = -3.
    (f-3) = (-3)</span>² - 3 * (-3) = 9 + 9 = 18 
    18 ≠ 3, so, this is not correct.

3. f(x)=x²<span>+2x when evaluated with -3 gives you the value of 3
</span>    Evaluated with -3 means that x = -3.
    f(-3) = (-3)² + 2 * (-3) = 9 - 6 = 3
    3 = 3, so this is correct.

4. f(x)=x²-3x when evaluated with -3 gives you the value of 3
    Evaluated with 3 means that x = 3.
    f(3) = (3)² - 3 * 3 = 9 - 9 = 0
    0 ≠ 3, so this is not correct.
6 0
4 years ago
Read 2 more answers
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