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Triss [41]
3 years ago
8

Please help i do not get it

Mathematics
1 answer:
Ierofanga [76]3 years ago
6 0
Your starting temperature was 29 degrees. it drops 5 degrees every hour. let the hours be X.

so, 29-5x would be the equation.

answer: 29-40 = -11. :)

explanation: multiply 5 times 8, because 9am to 4pm is 8 hours. this is 40. take your starting temp, 29 minus 40.

hope this helps
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Verify the identity below with work and/ or explanation. 2gh/sin^2θ = 2gh sec^2θ/sec^2θ-1 Thanks!
Orlov [11]

Answer:

identify is verified, see work below.

Step-by-step explanation:

Verify following identity

2gh/sin^2θ = 2gh sec^2θ/sec^2θ-1

use identity 1+tan^2(θ) = sec^2(θ) on denominator of right-hand-side

right-hand side

= 2gh sec^2(θ) / (sec^2(θ)-1)

=  2gh sec^2(θ) / (tan^2(θ))

=  2gh sec^2(θ) * (cos^2(θ) / sin^2(θ) )   [note: sec^2(θ) = 1/cos^2(θ)]

= 2gh * 1 / sin^2(θ)

= 2gh / sin^2(θ)

= left-hand side

Therefore identify is verified.

3 0
4 years ago
Write a story that describes the graph below.
Veseljchak [2.6K]

I'm not going to write a story, but here are a few prompts and idea to use:

- person who lost their money to a gambling addiction

- person who had to deal with the expenses of an accident they were in

- person who lost thier success after a scandal and with their fame went their money

- or maybe someone who became a criminal who got caught, so they lost all their money

8 0
3 years ago
Which is the distance between the point with the coordinates (-2, 3) and the line with the equation 6x - y = -3?
DedPeter [7]

Answer:

d. 12√37 / 37

Step-by-step explanation:

standard formula for the distance between a point (x₀,y₀) and a line ax+by+c=0 is |a*x₀ + b*y₀ + c| / √a²+b²

(x₀,y₀) : (-2 , 3)

ax+by+c=0 : 6x - y +3 = 0

x₀ = -2      y₀ = 3     a = 6       b = -1        c = 3

d = | 6*(-2) + (-1)*3 + 3 | / √6²+(-1)²

d = 12 / √37 = 12√37 / 37

3 0
3 years ago
Calculate the mean for samples for which the sample size and summation from nothing to nothing x∑x are given below.
Ierofanga [76]
In order to compute the mean, simply divide the sum over the number of 
element in the sample, like this:
1)\frac{\Sigma x_i}{10}= \frac{8282}{10}= 828.2

2)
\frac{\Sigma x_i}{10}= \frac{336336}{16}=21021
3 0
3 years ago
Amanda's average grade on a set of five test was 88%. She can remember only that the first four grade were 78%, 86%, 96%, and 94
Sergeeva-Olga [200]

Answer:

I think the answer is 92%.

4 0
3 years ago
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