What I would do with is just multiply the 125 by half an hour yeah or just multiply the ones we five by in half an hour and get your final answer I multiply the 1.25 by 1.2 and I got 1.5 + If I multiply the 1.25 + 2i would get 2.5
Answer: a-b+c+d =4
Step-by-step explanation:
The given system of equation is
![2x+8y=7\\4x-2y=9](https://tex.z-dn.net/?f=2x%2B8y%3D7%5C%5C4x-2y%3D9)
from this we have the following matrices
![A_1 =\begin{bmatrix}\\2 &8 \\ \\4&2 \\\end{bmatrix}\ ,X=\begin{bmatrix}\\x\\ \\y\\\end{bmatrix}\text{and}\ C=\begin{bmatrix}\\7\\ \\9\\\end{bmatrix}](https://tex.z-dn.net/?f=A_1%20%3D%5Cbegin%7Bbmatrix%7D%5C%5C2%20%268%20%5C%5C%20%5C%5C4%262%20%5C%5C%5Cend%7Bbmatrix%7D%5C%20%2CX%3D%5Cbegin%7Bbmatrix%7D%5C%5Cx%5C%5C%20%5C%5Cy%5C%5C%5Cend%7Bbmatrix%7D%5Ctext%7Band%7D%5C%20C%3D%5Cbegin%7Bbmatrix%7D%5C%5C7%5C%5C%20%5C%5C9%5C%5C%5Cend%7Bbmatrix%7D)
the given matrix A =![\begin{bmatrix}\\a &c \\ \\b &d \\\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5C%5Ca%20%26c%20%5C%5C%20%5C%5Cb%20%26d%20%5C%5C%5Cend%7Bbmatrix%7D)
On comparing Matrix
with Matrix A
![\begin{bmatrix}\\a &c \\ \\b &d \\\end{bmatrix}=\begin{bmatrix}\\2&8 \\ \\4 &-2 \\\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5C%5Ca%20%26c%20%5C%5C%20%5C%5Cb%20%26d%20%5C%5C%5Cend%7Bbmatrix%7D%3D%5Cbegin%7Bbmatrix%7D%5C%5C2%268%20%5C%5C%20%5C%5C4%20%26-2%20%5C%5C%5Cend%7Bbmatrix%7D)
we have the following values
a=2 ,b=4,c=8,d=-2
Thus a-b+c+d =2-4+8+(-2)=4
Answer:
18x
Step-by-step explanation:
2(3x+6x)
Based on the theory, the distance from the starting point to the return point = Arc length = 109.9 feet.
<h3>What is the Length of an Arc?</h3>
The arc length of a circle can be calculated with the radius and central angle using the arc length formula.
Arc length = ∅/360 × 2πr
Since the sector formed is a quarter circle, then ∅ = 90°.
Raidus (r) = 70 ft
Distance from the starting point to the return point = arc length.
Arc length = ∅/360 × 2πr = 90/360 × 2π(70)
Arc length = 109.9 feet
Therefore, based on the theory, the distance from the starting point to the return point = Arc length = 109.9 feet.
Learn more about the arc length on:
brainly.com/question/2005046
#SPJ1
we can always find the slope of any line by simply using two points on the line, say let's use (3,4) and (-1,2)
![\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-4}{-1-3}\implies \cfrac{-2}{-4}\implies \stackrel{\stackrel{\textit{common difference}}{\downarrow }}{\cfrac{1}{2}}](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B3%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-1%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20%5C%5C%5C%5C%5C%5C%20slope%20%3D%20m%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B2-4%7D%7B-1-3%7D%5Cimplies%20%5Ccfrac%7B-2%7D%7B-4%7D%5Cimplies%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bcommon%20difference%7D%7D%7B%5Cdownarrow%20%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%7D)