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Anastaziya [24]
2 years ago
15

It is not 9/18 or 1/2 PLEASE ANWSER CORRECTLY

Mathematics
2 answers:
pshichka [43]2 years ago
8 0

Answer:

7/8.

Step-by-step explanation:

5 weeks = 5*7 = 35 days.

So the fraction is 35/40

= (35/5) / (40/5)

= 7/8.

anastassius [24]2 years ago
6 0

Answer:

1/8 because you do 5 divided by 5 and 40 divided by 5 which gives you 8. Meaning, 1/8 is the answer.

Step-by-step explanation:

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Given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
Mamont248 [21]

Answer:

Step-by-step explanation:

From the given information:

a) To express the weekly profit as a function of price

Cost =C(q) = 1500 + 10q

Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²

Revenue = 50q - 0.1q²

Weekly profit = Revenue - Cost

P(q) = (50q -0.1q²) - (1500 + 10q)

P(q)= -0.1 q² + 40 q - 1500  

However, q = 500 - 10 p using p = 50 − 0.1q

P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500

P= -10 p² + 600 p - 6500

b)

The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0  

P' = 0

= -20p+600 = 0

20p = 600

p = 600/20

p = $30

c)

The maximum profit that can be made by the producer is:

P= -10(30)² + 600(30) - 6500

P = - 9000 + 18000 - 6500

P = $2500

5 0
3 years ago
3 women push a stalled car. Each woman pushes with a 425 N force. What is the mass of the
iogann1982 [59]

Answer:

1,500 Kg

Step-by-step explanation:

Formual for froce is given by

force = mass * acceleration

Force exerted by 1 woman = 425 N

no. of women exerting force = 3

Force exerted by 3 woman = 425 * 3 N = 1275 N

Acceleration produced by 1275 N force = 0.85 m/s^2

Using formula force = mass * acceleration

1275 = mass *  0.85 m/s^2

=> mass = 1275/ 0.85 m/s^2 = 1,500 Kg

Thus, mass of car is 1,500 Kg.

8 0
2 years ago
Which value of x is a solution of the inequality?
avanturin [10]

Answer:

3x-3>=9=>

3x>=12=>

x>=4

5 0
2 years ago
Read 2 more answers
The United States and Mexico stood on the brink of war until the _________ negotiated the dispute.
Korolek [52]
B. ABC Powers !! :-)
5 0
3 years ago
Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
LuckyWell [14K]

Answer:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

df = n_1 +n_2 -2 = 10+15-2= 23

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

\bar X_1 = 1085 sample mean for group 1

\bar X_2 = 1034 sample mean for group 2

n_1 = 10 sample size for group 1

n_2 = 15 sample size for group 2

s_1 = 52 sample deviation for group 1

s_2 = 61 sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0
3 years ago
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