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3 years ago

12

To kick off the summer, Colton is planning a "School's Out!" party for all his friends. He and his mom pick up a giant sub and a

vat of root beer from Subs & Suds. When they get to the park, they cut the sub into 18 equal sections. Each section is 1/3 of a foot long.

1 answer:

marshall27 [118]3 years ago

4 0

Answer:

(a)6 feet

(b)24 sections

Step-by-step explanation:

(a)We are required to find the length of the Giant Sub.

If each section is 1/3 of a foot long and there are 18 equal parts.

Length of the Giant Sub =

Length per Section X Number of Sections

= 1/3 X 18 = 6 feet

(b)If each section is 1/4 of a feet long

Length of the Giant Sub =

Length per Section X Number of Sections

6= 1/4 X Number of Sections

Number of Sections =6 X 4 =24 sections

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Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

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So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

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Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

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$n(B) = 77$

P(B) is then calculated as:

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Solving (c): P(A n B)

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This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

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$P(A\ n\ B) = \frac{22}{100}$

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This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

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