the answer is 20
1/10 of 200 is 200* 1/10 = 200/10 which is 20
Answer:
1963.2 pounds (lbs.)
Step-by-step explanation:
Things to understand before solving:
- - <u>Normal Probability Distribution</u>
- The z-score formula can be used to solve normal distribution problems. In a set with mean ц and standard deviation б, the z-score of a measure X is given by:
The Z-score reflects how far the measure deviates from the mean. After determining the Z-score, we examine the z-score table to determine the p-value associated with this z-score. This p-value represents the likelihood that the measure's value is less than X, or the percentile of X. Subtracting 1 from the p-value yields the likelihood that the measure's value is larger than X.
- - <u>Central Limit Theorem</u>
- The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean ц and standard deviation б , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean ц and standard deviation
As long as n is more than 30, the Central Limit Theorem may be applied to a skewed variable. A specific kind of steel cable has an average breaking strength of 2000 pounds, with a standard variation of 100 pounds.
This means, ц = 2000 and б = 100.
A random sample of 20 cables is chosen and tested.
This means that n = 20,
Determine the sample mean that will exclude the top 95 percent of all size 20 samples drawn from the population.
This is the 100-95th percentile, or X when Z has a p-value of 0.05, or X when Z = -1.645. So
- By the Central Limit Theorem
<h3>Answer:</h3>
The sample mean that will cut off the top 95% of all size 20 samples obtained from the population is 1963.2 pounds.
Step-by-step explanation:
A Maclaurin series is a Taylor series that's centered at 0.
f(x) = ∑ₙ₌₀°° f⁽ⁿ⁾(0) / n! xⁿ
If we substitute f⁽ⁿ⁾(0) = (n + 1)!:
f(x) = ∑ₙ₌₀°° (n + 1)! / n! xⁿ
f(x) = ∑ₙ₌₀°° (n + 1) xⁿ
Use ratio test to find the radius of convergence.
lim(n→∞)│aₙ₊₁ / aₙ│< 1
lim(n→∞)│[(n + 2) xⁿ⁺¹] / [(n + 1) xⁿ]│< 1
lim(n→∞)│(n + 2) x / (n + 1)│< 1
│x│< 1
R = 1
The answer should be B) if my math is correct