Question

Experıment wıth systems of equatıons 2x+4y =8....(1) 2x+2y=2....(2) answer?

Answer 1

Answer:

Solve by substitution;

2x +4y =8 ...(1)

$2x + 4y = 8 \\ \\ 4y = 8 - 2x \\ \\ y = \frac{8 - 2x}{4} \\ \\ y = 2 - \frac{x}{2}$

We substitute y into the second equation.

2x + 2y=2 ... (2)

$2x + 2y = 2 \\ \\ 2x + 2(2 - \frac{x}{2} ) = 2 \\ \\ 2x + 4 - x = 2 \\ \\ x + 4 = 2 \\ x = 2 - 4 \\ x = - 2$

And we substitute x into the equation y .

$y = 2 - \frac{x}{2} \\ \\ y = 2 - \frac{( - 2)}{2} \\ \\ y = 2 + 1 \\ y = 3$

(x,y) —> (–2 , 3 )

I hope I helped you^_^