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kodGreya [7K]
2 years ago
7

32i-4+2=6-42i-3 help

Mathematics
1 answer:
Dmitrij [34]2 years ago
8 0
15i would be your best answer
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Help needed....
LenKa [72]
The answer is C) y = 4x - 3
B and D can be eliminated by substituting 0 for x in each...the result is not -3
Now you have a 50/50 chance of getting the question correct
5 0
3 years ago
Order the numbers from least to greatest. List the numbers as your final answer. 4, 7, -2, 25, 49, 63, 13, -22, 19, -13, 4/4, 34
sp2606 [1]
-22 , -13, -3, -2 , 4/4, 4, 7, 13, 19, 25, 34, 49, 63
4 0
3 years ago
Read 2 more answers
Jill fish weighs 8 times as much as her parakeet. Together, the pets weigh 63 ounces. How much does the fish weigh?
sleet_krkn [62]

63 \times 8
=
504
8 0
3 years ago
Match the polygons formed by the sets of points with their perimeters (rounded to the nearest hundredth). Tiles A(1, 1), B(6, 13
Nesterboy [21]
Hello,
Please, see the attached files.
Thanks.

5 0
3 years ago
Read 2 more answers
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
3 years ago
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