Jill fish weighs 8 times as much as her parakeet. Together, the pets weigh 63 ounces. How much does the fish weigh?

What is the solution to the inequality?<br><br> −4x−8>−20<br> pls hurry

Sergeu [11.5K]

Answer:

x < 3

Step-by-step explanation:

−4x−8>−20

Add 8 to each side

−4x−8+8>−20+8

-4x> -12

Divide each side by -4, remembering to flip the inequality

-4x/-4 < -12/-4

x < 3

3 0

3 years ago

Robert needs to cut four shelves from a board that is 2.5 meters long. The second shelf is 18 centimeters longer than twice the

USPshnik [31]

1st shelf: 48cm
2nd shelf: 114cm
3rd shelf: 36cm
4th shelf: 52cm
Total length: 250cm or 2.5m

7 0

3 years ago

when the sum of an unknown number z and twenty two is divided by the same unknown number,the quotient is twelve what is the unkn

Anarel [89]

The unknown number . . . . . (z)

The sum of the unknown number and 22 . . . . . (z + 22)

The sum of the unknown number and 22
divided by the same unknown number . . . . . . . (z + 22) / z

You said that quotient is 12. (z + 22) / z = 12

Multiply each side by 'z' : (z + 22) = 12 z

Subtract 'z' from each side: 22 = 11 z

Divide each side by 11 : 2 = z .

6 0

3 years ago

Cost $4 since 0.25•20=4. Together,they would cost Jada $6 , leaving her with $6 . 35 ounces of peanuts. If Jada wants 20 ounces

Viefleur [7K]

Answer:

The Answer is....

Step-by-step explanation:

Need more info and question needs to be explained better

6 0

3 years ago

Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How

Scorpion4ik [409]

let's check how much is it after 2 years firstly.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275$

Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}$

4 0

3 years ago