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kolbaska11 [484]
2 years ago
15

I’ll give you brainliest

Mathematics
2 answers:
Luda [366]2 years ago
8 0
The answer to your question is number 2
mixas84 [53]2 years ago
7 0

Answer:

the answer you want is number 2

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The length of the base of a scalene triangle is 22 meters and the height is 14 meters. Find the area of the scalene triangle
Nezavi [6.7K]

Answer:

Area is 154 square meters

Step-by-step explanation:

Well lets think about this

If I take a rectangle and cut it into half diagonally I would get 2 triangles right?

So if I have 2 triangles of the same height and base I can make a rectangle

to find the area of a rectangle I do length times width

So lets take our scalene triangle and multiply our base with its width and then divide by 2

22*14 = 308

308/2 is 154

5 0
3 years ago
Round 288 to the nearest tenth
cricket20 [7]
290

hopefully i could help ;)

6 0
3 years ago
QUICK QUICK PLEASE! 1 MINUTE ONLY! WITH EXPLANATION PLEASE!
Dmitriy789 [7]

Answer:

Step-by-step explanation:

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5 0
3 years ago
If x^3=64, what is the value of x?
pickupchik [31]

Answer:

x=4

Step-by-step explanation:

all you need to do is the 3rd root of 64

which is 4.

6 0
3 years ago
In a missile-testing program, one random variable of interest is the distance between the point at which the missile lands and t
Arisa [49]

Answer:

Step-by-step explanation:

From the given data

we observed that the missile testing program

Y1 and Y2 are variable, they are also independent

We are aware that

(Y_1)^2 and (Y_2)^2 have x^2 distribution with 1 degree of freedom

and V=(Y_1^2)+(Y_2)^2 has x^2 with 2 degree of freedom

F_v(v)=\frac{e^{-\frac{v}{2}}}2

Since we have to find the density formula

U=\sqrt{V}

We use method of transformation

h(V)=\sqrt{U}\\\\=U

There inverse function is h^-^1(U)=U^2

We derivate the fuction above with respect to u

\frac{d}{du} (h^-^1(u))=\frac{d}{du} (u^2)\\\\=2u^2^-^1\\\\=2u

Therefore,

F_v(u)=F_v(h-^1)(u)\frac{dh^-^1}{du} \\\\=\frac{e^-\frac{u^-^}{2} }{2} (2u)\\\\=e^-{\frac{u^2}{2} }U

8 0
3 years ago
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