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3 years ago

If smart please help me!!!!..!

Mathematics

1 answer:

Salsk061 [2.6K]3 years ago

4 0

Answer:

<h2>None of the other answer are correct. </h2>

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M(x)=x^2-3x N(x)=x-5 MN(-1)= ? A.18 B.-20 C.-22 D. -24

schepotkina [342]

Answer:

d. -24

Step-by-step explanation:

M(-1)=(-1)^2-3(-1)

M(-1)=1+3

M(-1)=4

N(-1)=-1-5

N(-1)=-6

MN(-1)=(4)(-6)

MN(-1)=-24

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4 years ago

I’m doing the concept on how do you determine any of the six trigonometric functions using reference angles to find trig values

Softa [21]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the solution to the system of equations below?

Nady [450]

A))))))(9,3)
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8 0

3 years ago

What is the price per ounce for 10 ounces and the cost is $1.75

ollegr [7]

Answer:

The price per ounce is $0.175.

Step-by-step explanation:

Given:

Number of ounces = 10

Price of 10 ounces = $1.75

We know that, from unitary method, price of a unit quantity is given as:

$\textrm{Unit rate}=\frac{\textrm{Total price}}{\textrm{Number of quantities}}$

Here, the number of quantities correspond to the number of ounces.

Total price corresponds to the price of the 10 ounces which is $1.75.

Now, unit rate or price per ounce is given as:

Price per ounce = $\frac{1.75}{10}$

Price per ounce = $0.175

Therefore, the price per ounce is $0.175.

3 0

4 years ago

At a certain coffee shop, all the customers buy a cup of coffee and some also buy a doughnut. The shop owner believes that the n

wolverine [178]

Answer:

(1) The probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2) The shop owner has no reasonable chance to expect earning a profit more than $300.

(3) The probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

Step-by-step explanation:

Let X = number of cups of coffee sold and Y = number of donuts sold.

The random variable X follows a Normal distribution with parameters μ = 320 and σ = 20.

The random variable Y follows a Normal distribution with parameters μ = 150 and σ = 12.

The shop owner opens the shop 6 days a week.

(1)

Compute the probability that the shop owner sells over 2000 cups of coffee in a week as follows:

$P(X>2000)=P(\frac{X-\mu}{\sigma}>\frac{2000-(6\times320)}{6\times20})\\=P(Z>0.67)\\=1-P(Z$

Thus, the probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2)

The equation representing the profit earned on selling 1 cup of coffee and 1 doughnut in a day is:

P = 0.5X + 0.4Y

Compute the probability that the shop owner earns more than $300 as profit as follows:

$P(Profit>300)=P(\frac{Profit-\mu}{\sigma}>\frac{300-((0.5\times320)+(0.4\times150))}{\sqrt{0.5^{2}(20)^{2}+0.4^{2}(12)^{2}}})\\=P(Z>7.21)\\\approx0$

The probability of earning a profit more then $300 is approximately 0.

Thus, the shop owner has no reasonable chance to expect earning a profit more than $300.

(3)

The expression representing the statement "he'll sell a doughnut to more than half of his coffee customers" is:

Y > 0.5X

Y - 0.5X > 0

Compute the probability of the event (Y - 0.5X > 0) as follows:

$P(Y - 0.5X > 0)=P(\frac{(Y - 0.5X) -\mu}{\sigma}>\frac{0-(150-(0.5\times320}{\sqrt{12^{2}+0.5^{2}20^{2}}})\\=P(Z>0.64)\\=1-P(Z$

Thus, the probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

8 0

3 years ago