Hey does anybody live in pickens on here

Start with the point A (3, 1). Translate the point 1 unit to the left and 4 units down. What are the new coordinates of the poin

Over [174]

This is the transformations: See the picture, here we find the coordinate:

A' = (2,-3) and A''=(0.5,-2). There is many ways to get back to A from A'', i have showed one way (the red lines). This is done by going 5 units right and then 6 units up.

see image at https://imgur.com/a/fWQl8

3 0

3 years ago

Hola alguien sabe y me explique como puedo resolver esto me dice que use los numeros dados y que haga una familia de hechos para

VMariaS [17]

5+4=9 es uno 4+5=9 es Otro 9-5=4 es Otro 9-4=5

6 0

3 years ago

A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In

lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of males having blood disorder= $\frac{250}{1000}$ = 0.25

$\hat p_2$ = sample proportion of females having blood disorder = $\frac{275}{1000}$ = 0.275

$n_1$ = sample of males = 1000

$n_2$ = sample of females = 1000

$p_1$ = population proportion of males having blood disorder

$p_2$ = population proportion of females having blood disorder

Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.

So, 95% confidence interval for the difference between the population proportions, ( $p_1-p_2$ ) is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

P( $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ < ( $p_1-p_2$ ) < $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ) = 0.95

95% confidence interval for ( $p_1-p_2$ ) =

[ $(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ , $(\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ]

= [ $(0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ , $(0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }$ ]

= [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0

3 years ago

Two lines are intersected by a third line. If 2 6, which must be true about 2? 2 5 2 is complementary to 5. m2 = m8 2 is supplem

sineoko [7]

If this scenario is a pair of parallel lines intersected by a transversal then it is true that
2 = 6
Then, among the choices, the statement that is true is
2 is supplementary to 8 since 6 is supplementary to 8
By transitivity property, 2 is supplementary 8

4 0

3 years ago

Read 2 more answers

What is the value of p in the linear equation ? −4 −2 2 4

Snezhnost [94]

Answer:

p = -2

Step-by-step explanation:

O we have to solve this equation:

24p + 12 - 18p = 10 + 2p - 6

First, we will operate what we have in both sides:

24p - 18p + 12 = 10 - 6 + 2p

6p + 12 = 4 + 2p

We substract 2p in both sides and 12 too.

6p + 12 - 2p - 12 = 4 + 2p - 2p - 12

4p = -8

Now, we divide both sides by 4

4p/4 = -8/4

7 0

3 years ago

Read 2 more answers