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Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

In which




So

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Answer:
5=5
Step-by-step explanation:
Answer:
4^n-1
Step-by-step explanation:
So given sequence is a geometric sequence where terms increase or decrease by a constant common ratio(r)
Formula to find terms in Geometric sequence is " ar^n-1 where a is first term , r is common ratio and n is number of items
In this case , first term (a) is 1 , common ratio(r) is succeeding term/preceding term = 4/1 = 4 and number of items be (n).
Applying "ar^n-1 " we get,
1*4^n-1 which is , 4^n-1
Thats the formula which represents the situation....