Rita received 24 phone calls on the first evening, and 19 phone calls on the second evening and 48 phone calls on the third evening at the call center.
Step-by-step explanation:
As per given details,
Rita received a total of 91 phone calls at the call center over the last three evenings.
Let us assume the number of phone calls Rita received in the first evening is X.
The second evening Rita received 5 fewer calls than the first evening
=>X-5
The third evening Rita received 2 times as any calls as the first evening
=>2X
Now as given sum of total number of calls received in the three evenings is
X + X-5 + 2X = 91
4X - 5 = 91
4X = 96
X =24.
Therefore total calls received on first evening is X = 24
On the second evening X-5 = 24-5 = 19
On the third evening 2X = 48.
5+15=20
20x3=60
I'm probably wrong, but thats how I understood the question.
Answer:
n=9
Step-by-step explanation:
You use reverse PEMDAS.
First you would divide by 3 on both sides. This should give you:
n²=81
Then you would find 
. Which is 9.
multiply the top equation by 3, multiply the bottom equation by 4, then subtract the bottom equation from the top equation
multiply the top equation by 3, multiply the bottom equation by -2, then add the equations
