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3 years ago

F(x)= x^2 - 2x + 7 Find F(-1)

Mathematics

2 answers:

Leni [432]3 years ago

8 0

Answer:f(1)=-4, f(1)=1

Just substitute the value to the x, Like this.

F(x)=x²+2x-7

F(1)=(1)²+2(1)-7

=1+2-7

=3-7

=-4

Step-by-step explanation:

Levart [38]3 years ago

6 0

Answer:

f(- 1) = 10

Step-by-step explanation:

Substitute x = - 1 into f(x) , that is

f(- 1) = (- 1)² - 2(- 1) + 7 = 1 + 2 + 7 = 10

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The skittles jar has a radius of 3.5 cm and a height of 11.5 cm. using the two given boxes for reference what would be a good es

Bond [772]

C) 1059 skittles

Step-by-step explanation:

We know that the first container held 192 skittles. Knowing the dimension of the container we can calculate the volume of 192 skittles:

Volume of 192 skittles = 5 × 4 × 4 = 80 cm³

Volume of 1 skittle = 80 / 192 = 0.42 cm³

We also know that the second container held 258 skittles. Knowing the dimension of the container we can calculate the volume of 258 skittles:

Volume of 258 skittles = 12 × 3 × 3 = 108 cm³

Volume of 1 skittle = 108 / 258 = 0.42 cm³

We found that the volume of 1 skittle is equal to 0.42 cm³. Now we calculate the volume of the skittles jar:

volume of cylinder = π × radius² × height

volume of skittles jar = 3.14 × 3.5² × 11.5 = 442 cm³

Now we can calculate the number of skittles in the jar:

number of skittles in the jar = volume of the jar / skittle volume

number of skittles in the jar = 442 / 0.42 = 1052 which is close the C) 1059

Learn more about:

volume of cylinder

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7 0

3 years ago

Graphing linear inequalities digital escapes puzzle 4

Vadim26 [7]

Answer:

1 - F

2 - B

3 - H

4 - A

Step-by-step explanation:

m = -2

b = 4

y < mx + b

y < -2x + 4

m = 1

b = -2

y < mx + b

y < 1x -2

y < x - 2

m = -4

y <= mx + b

H is the only one that follows those rules

m = 1

y >= mx + b

A is the only one that follows those rules

5 0

2 years ago

the surface areas of two similar solids are 1,008cm^2 and 1,372cm^2. the volume of the larger solid is 1,801cm^3. find the volum

Anni [7]

<span>Remember the ratios
Linear = a : b
Area = a^2 : b^2
Volume = a^3 : b^3

Hence area ratios are 1008 : 1372
Becomes linear ratios of Sqrt(1008) : sqrt(1372) :: 31.749 : 37.040
Volume ratios becomes 31.749^3 : 37.040^3 :: 32002.96 : 50817.46

Hence

32002.96 / 50817.46 = Vol (S) / 1801 cm^3
Vol(s) = 32002.96 X 1801 / 50817.46 = 1134.20cm^3 ( nearest hundredth).

</span>

8 0

3 years ago

A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol

bagirrra123 [75]

Answer:

a) 0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b) 0.118 = 11.8% probability that exactly 4 of the calls involve a fax message

c) 0.904 = 90.4% probability that at least 4 of the calls involve a fax message

d) 0.786 = 78.6% probability that more than 4 of the calls involve a fax message

Step-by-step explanation:

For each call, there are only two possible outcomes. Either it involves a fax message, or it does not. The probability of a call involving a fax message is independent of other calls. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

25% of the incoming calls involve fax messages

This means that $p = 0.25$

25 incoming calls.

This means that $n = 25$

a. What is the probability that at most 4 of the calls involve a fax message?

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$ .

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001$

$P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006$

$P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025$

$P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064$

$P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.001 + 0.006 + 0.025 + 0.064 + 0.118 = 0.214$

0.214 = 21.4% probability that at most 4 of the calls involve a fax message

b. What is the probability that exactly 4 of the calls involve a fax message?

$P(X = 4) = C_{25,4}.(0.25)^{4}.(0.75)^{21} = 0.118$

0.118 = 11.8% probability that exactly 4 of the calls involve a fax message.

c. What is the probability that at least 4 of the calls involve a fax message?

Either less than 4 calls involve fax messages, or at least 4 do. The sum of the probabilities of these events is 1. So

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$ . Then

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{25,0}.(0.25)^{0}.(0.75)^{25} = 0.001$

$P(X = 1) = C_{25,1}.(0.25)^{1}.(0.75)^{24} = 0.006$

$P(X = 2) = C_{25,2}.(0.25)^{2}.(0.75)^{23} = 0.025$

$P(X = 3) = C_{25,3}.(0.25)^{3}.(0.75)^{22} = 0.064$

$P(X$

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.096 = 0.904$

0.904 = 90.4% probability that at least 4 of the calls involve a fax message.

d. What is the probability that more than 4 of the calls involve a fax message?

Very similar to c.

$P(X \leq 4) + P(X > 4) = 1$

From a), $P(X \leq 4) = 0.214)$

Then

$P(X > 4) = 1 - 0.214 = 0.786$

0.786 = 78.6% probability that more than 4 of the calls involve a fax message

8 0

3 years ago

Which is an example of a short-term investment?

katovenus [111]

Checking account is a short term investment

8 0

3 years ago