This is because
(that is, replace any instance of <em>x</em> in the definition of <em>g</em> with √<em>x</em> )
and
(replace any <em>x</em> in <em>f</em> with √<em>x</em> - 1)
Also acceptable:
(assuming <em>x</em> is not negative)
Answer:
3x^2-4x+20/x^2-5x .
Step-by-step explanation:
The given rational expression is:
3x/x-5 - 4/x
Hence to find the difference of the rational numbers we have to take the L.C.M of the denominators:
Thus the L.C.M of x-5 and x is (x-5)(x) and then solve for the numerator:
x(3x) - 4(x-5)/(x-5)(x)
Now solve the numerator and denominator:
3x^2-4x+20/x^2-5x
Thus the answer is 3x^2-4x+20/x^2-5x ....
The answer is .5. That is the answer because .5/10 = .05.
i) Plan A: 21/0,12 = 175 <min of calls>
Plan B: 15/0,14 ≈ 107 <min of calls>
=> 2 plans cost the same 107 min of calls
ii) The cost when 2 plans cost the same:
- Plan A: 107 × 0,12 = 12,84$ ≈ 13$
- Plan B: 107 × 0.14 ≈ 15$
Answer: i) 107 ii) A: 13$ B: 15$
Answer:
<em>x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A</em>
Step-by-step explanation:
See steps below;
I would prefer answering this question by completing the square, rather than applying a quadratic formula;
3x^2 - 6x - 12 = 0, ⇒ Add 12 to either side,
3x^2 - 6x = 12, ⇒ Divide either side by 3,
x^2 - 2x = 4, ⇒ Write the equation in the form x^2 + 2ax + a^2 = (x + a)^2,
x^2 - 2ax + a^2 = 4 + a^2, ⇒ Solve for a
2ax = -2x,
a = - 1, ⇒ Substitute value of a,
x^2 - 2x + 1 = 4 + 1,
( x - 1 )^2 = 5, ⇒ Solve for x,
x = √5 + 1, and x = - √5 + 1,
In other words; <em>Solution : x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A</em>
