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labwork [276]
3 years ago
14

Someone plss helpppppp​​

Mathematics
2 answers:
OLga [1]3 years ago
4 0
Can you text me and type it so I can solve it?
marshall27 [118]3 years ago
3 0

\displaystyle \left \{\begin{array}{ccc}  2y=x-12 \\\\y=2x^2+3x-4  \end{array } \right. \Rightarrow \begin{cases} y =\dfrac{x-12}{2}  \\\\ 2x^2+3x-4=\dfrac{x-12}{2} \end{cases }  \Rightarrow   \\\\\\ 2x^2+3x-4=\frac{x-12}{2}  \\\\4x^2+6x-8=x-12 \\\\4x^2+5x+4=0 \\\\ \rm D=25-4\cdot 4\cdot 4=-39  \\\\D

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Rufina [12.5K]
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5 0
3 years ago
Which best describes the relationship between the two triangles below?
neonofarm [45]

Answer:

It’s the bottom answer.

Step-by-step explanation:

hope I helped

6 0
3 years ago
Rashid is paid by the hour. He earned $50 for a 4-hour workday. How much does he earn for a 5 1/4-hour workday?
xeze [42]
ANSWER: $65.63

$50 divided by 4 hours = $12.50 per hour
1/4 can also be written as the fraction 0.25
So 5 1/4 hours is the same as 5.25 hours
$12.50 per hour x 5.25 hours = $65.625 rounded to the nearest cent = $65.63
5 0
4 years ago
Which point is on the graph of f(x) = 3 x 5^x?
Harlamova29_29 [7]

Answer:

C

Step-by-step explanation:

To determine which point lies on the graph, substitute the x-coordinate into f(x) and if the value is equal to the y-coordinate then the point is on the graph

A (15, 1)

f(15) = 3 × 5^{15} ≠ 1 ← not on graph

B (0, 15)

f(0) = 3 × 5^{0} = 3 × 1 = 3 ≠ 15 ← not on graph

C (1, 15)

f(1) = 3 × 5^{1} = 3 × 5 = 15 ← lies on graph

D (0, 0)

f(0) = 3 × 5^{0} = 3 × 1 = 3 ≠ 0 ← not on graph



5 0
3 years ago
Read 2 more answers
Determine the solution to the system of equations given below y=x^2-5x+15
Maslowich

Answer:

x=(5+i*sqrt(35))/2, (5-i*sqrt(35))/2

Step-by-step explanation:

Use the quadratic formula with the following values.

a = 1

b = -5

c = 15

Substitute and simplify.

(5+-sqrt((-5)^2-4*(1*15)))/2*1

x = (5+-i*sqrt(35))/2

When you get a negative number inside the square root, remember that you can pull out i to make the number inside positive.

3 0
3 years ago
Read 2 more answers
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