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3 years ago

Find the value of x with all work, parallel lines and transversal lines

Mathematics

1 answer:

musickatia [10]3 years ago

3 0

Answer: no idea

Step-by-step explanation:

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How do you do a expression

8090 [49]

1. get rid of your parenthesis
2. in order to do so you must look inside of the parenthesis and check if you have any like terms if so combine them
3. next use the distribution property or otherwise known as the rainbow
4. if you have an exponent to the right of your parenthesis then use the exponent rule
5. combine like terms by adding coefficients
6. finally combine the constants

5 0

3 years ago

Your balance sheet shows $6,400 worth of inventory in hair products. Items are recorded in inventory at cost, and the average co

andreyandreev [35.5K]

Answer:

Units of hair products = 2634 units

Step-by-step explanation:

Given that:

Worth of products in the inventory = $6400

Average cost per unit = $2.43

Number of units = $\frac{Total\ worth}{Per\ unit\ cost}$

Number of units = $\frac{6400}{2.43}$

Number of units = 2633.73

Rounding off to nearest whole number = 2634 units

Hence,

Units of hair products = 2634 units

4 0

3 years ago

15 + 4x = 12 + x nm jjk kj k j jk kj k kj kjkj

Marta_Voda [28]

Answer:

x = −1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

3 years ago

I need help in this math number 7,I got the picture here for u to know what to do because I don’t understand the question ppplll

tia_tia [17]

You have to find a common denominator for both fractions. I chose the denominator to be 10, so the 1/2 will become 5/10, and 1/5 will become 2/10.

Subtract 5/10 from 2/10. You will get -3/10.

Answer: -3/10

You can check your answer by solving 1/2-3/10=1/5 to see if it is true. (It is:)

5 0

3 years ago