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Citrus2011 [14]
3 years ago
11

PLEASE SOLVE AND SHOW STEPS!! ILL PAY REAL MONEY! DM ME

Mathematics
2 answers:
aleksandrvk [35]3 years ago
8 0

Answer:

z=k-\frac{8T}{9}  -\frac{a}{9}

Step-by-step explanation:

9k-8T=9z+a\\9k-8T-a = 9z\\\frac{9k-8T-a }{9}= \frac{9z}{9} \\k-\frac{8T}{9}  -\frac{a}{9} = z\\z=k-\frac{8T}{9}  -\frac{a}{9}

Alisiya [41]3 years ago
7 0

Answer:

how much tho?

Step-by-step explanation:

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Compute the sales tax on the following transactions. An article retails for $37.50. The city sales tax is 6%, and the federal ex
ratelena [41]
First you must find the rate of both taxes. Since its 8% and 6%, you must add them both together, then divide them by 100. 

14/100 = .14

Then for both rates you must add 1 because it is a tax increase.

1 + .14 = 1.14

Finally times 37.50 with 1.14

37.50(1.14) = <span>42.75
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<span>$42.75 is the answer.</span>

 
7 0
3 years ago
Read 2 more answers
Which describes the correlation shown in the scatterplot?
xenn [34]

Answer:

I don't know..

Sorry for spamming...

6 0
3 years ago
Solve the following formula for x y = 7 m x − 8 b
katovenus [111]

Answer: It depends on which variable you're solving for.

Step-by-step explanation:

Solving for b: b=7/8mx + -1/8xy

Solving for m: m=xy+8b

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                                   7x

Solving for x: x=-8b

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                          -7m+y

Solving for y: y=7mx-8b

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7 0
2 years ago
A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we
weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

        P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample mean weighing of specimen = \frac{3.412+3.416+3.414}{3} = 3.414 g

            \sigma = population standard deviation = 0.001 g

            n = sample of specimen = 3

            \mu = population mean

<em>Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5% level

                                                            of significance are -2.5758 & 2.5758}

P(-2.5758 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X - \mu} < 2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

P( \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } } ]

                                             = [ 3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } } , 3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } } ]

                                             = [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0
3 years ago
I got nut in my but just finished giving head locked up with the feds took a lot of meds I gotta go to bed before i cut my dread
Evgen [1.6K]

Answer:

what are you talking about???

Step-by-step explanation:

brainliest and chill bro

5 0
3 years ago
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