For any circle, the area A = πr² (where r is the radius)
The radius is always half the length of the diameter.
Since our diameter is 12, our radius must be 6.
Let's plug 6 in for r in our equation.
A = π(6)²
<em>6² = 6×6 = 36
</em>A = 36π in²
For π = 3.14...
A = 36×3.14 = 113.04 in²
£1=100p
100-22=78p
He gets 78p
8x + 16 = 8( x + 2)
6x + 12= 6( x + 2)
8(x + 2). times 4x
2o 6( x + 2)
cancel (x + 2)
8 times 4x = 32x simplify = 4x
20 6 120 15
Hey ! there
Answer:
- <u>Option </u><u>D.</u><u> </u><u>39</u> is correct answer
Step-by-step explanation:
In this question we are given an expression that is <u>x³</u><u> </u><u>+</u><u> </u><u>x²</u><u> </u><u>+</u><u> </u><u>x</u> and <u>value </u><u>of </u><u>x </u><u>is </u><u>equal </u><u>to </u><u>3 </u><u>.</u> And we are asked to find the <u>value of expression</u> when value of x is 3 .
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
<u></u>
Now substituting value of x as 3 in it ,
- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>value </u><u>of </u><u>expression</u><u> </u><u>when </u><u>x </u><u>is </u><u>equal </u><u>to </u><u>3 </u><u>is </u><u>39</u><u> </u><u>.</u>
- <u>Therefore</u><u> </u><u>,</u><u> </u><u>O</u><u>ption </u><u>D</u><u> </u><u>is </u><u>correct</u><u>. </u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>