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Gemiola [76]
3 years ago
7

Which number can each term of the equation be multiplied by to eliminate the fractions before solving? -3/4m-1/2=2+1/4m​

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

* 2/3 / formula then multiply the numbers then you get the answer

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You want to mix a 5% blue dye with a 20% blue dye to make a 12% blue dye. The function y =100(0.05)+x(0.2)/100+x gives the conce
Natalija [7]
Y = 12% = 0.12

y = 100(0.05) + x(0.2) / 100 + x
0.12 = 5 + 0.2x / 100 + x
0.12( 100 + x ) = 5 + 0.2x
12 + 0.12x = 5 + 0.2x
7 = 0.08x
x = 87.5

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3 years ago
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3 years ago
The table of values represents the function t(x) and the graph shows the function g(x).
IrinaK [193]

Answer:

  The maximum value of the table t(x) has a greater maximum value that the graph g(x)

Step-by-step explanation:

The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.

The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).

The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...

  the maximum value of t(x) is greater than the maximum value of g(x)

8 0
3 years ago
Harold earns $10.50 per hour working at a doctor's office. On Monday he spent 1 5/12 hours filing paperwork, 1 3/4 sending email
Lana71 [14]

Answer:

the total earnings is $58

Step-by-step explanation:

The computation of earnings is shown below:

= Time spent in filling paperwork + time spent in sending emails + time spent in making appointments

= (1 5 ÷ 12 × $10.50)  + (1 3 ÷ 4 × $10.50)  + (2 1 ÷ 3 × $10.50)

= 14.875 + 18.375 + 24.50

= $57.75

Hence, the total earnings is $58

The same is to be considered

6 0
3 years ago
Pwease help <br> I need an answer right away<br> Thank you
Triss [41]
The answer is 150cm.
4 0
3 years ago
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