What is the equation of the line, first written in point-slope form and then written in slope-intercept form?
2 answers:
Point-slope form is
y - y1 = m(x - x1), where the (x1, y1) is one of the points.
First find the slope, which is change in y over change in x, or
The example points
(x1, y1) and (x2, y2) are now
( 3, 21 ) and ( 6, 12 ).
Now plug the slope and one of the points into the formula
To write in slope-intercept form, y = mx + b, simply solve for y.
y - y1 = m(x - x1), where the (x1, y1) is one of the points.
First find the slope, which is change in y over change in x, or
The example points
(x1, y1) and (x2, y2) are now
( 3, 21 ) and ( 6, 12 ).
Now plug the slope and one of the points into the formula
To write in slope-intercept form, y = mx + b, simply solve for y.
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Answer:
positive
Step-by-step explanation:
the discriminant of the function is postive.
because from the graph we notice that it has 2 intercepts on x-axis, which means the function has 2 real solution when y=0
that implies the discriminant is positive.
if we have 2 distinct real solution
if we have no real solution but 2 complex solutions
if we have 2 identical real solution