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kkurt [141]
2 years ago
9

I need help pls help me

Mathematics
1 answer:
alina1380 [7]2 years ago
8 0
Length times width.
6cm • 4cm = 24 cm^2


I hope this helps! Let me know if you have any questions! Good luck on the rest of your assessment!

Mark this as Brainliest if you get a chance:)
You might be interested in
The number of tomato plants Jeff planted went from 4 last year to 12 this year. Find the percent increase.​
Dafna1 [17]
200%

We find the difference, then divide that by the original. 12-4/4 = 8/4 = 2
Multiply by 100 to get the percentage, = 200%

Also, adding 4 would be a 100% increase, and adding 8 is twice that, so 200%.
6 0
2 years ago
If z = f(x, y), where f is differentiable, and x = g(t) y = h(t) g(9) = 6 h(9) = 4 g' (9) = −6 h' (9) = 4 fx(6, 4) = 9 fy(6, 4)
horsena [70]

Answer:

dz / dt = -50

Step-by-step explanation:

To solve the chain rule must apply, we have all the necessary values to make the calculation, as follows:

using the chain rule, we find:

dz / dt = (∂z / ∂x) * (∂x / ∂t) + (∂z / ∂y) * (∂y / ∂t)

Evaluating when t = 9, we have to:

fx (6, 4) * g '(9) + fy (6, 4) * h '(9)

We know that g '(9) = −6; h '(9) = 4; fx (6, 4) = 9; fy (6, 4) = 1

Replacing:

(9 * -6) + (1 * 4) = -50

Por lo tanto dz / dt = -50

6 0
3 years ago
Help. Do not take advantage of the points, please.
Arte-miy333 [17]

Answer:

?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Hypothesis testing on samples with fewer than 30 participants can be carried out by using the t-value for the corresponding leve
Eva8 [605]

Answer: true

Step-by-step explanation:

Z-tests are statistical calculations that can be used to compare the population mean to a sample mean The z-score is used to tellsbhow far in standard deviations a data point is from the mean of the data set. z-test compares a sample to a defined population and is typically used for dealing with problems relating to large samples (n > 30). Z-tests can also be used to test a hypothesis. Z-test is most useful when the standard deviation is known.

Like z-tests, t-tests are used to test a hypothesis, but a t-test asks whether a difference between the means of two groups is not likely to have occurred because of random chance. Usually, t-tests are used when dealing with problems with a small sample size (n < 30).

Both tests (z-tests and t-tests) are used in data with normal distribution (a sample data or population data that is evenly distributed around the mean).

3 0
3 years ago
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
Read 2 more answers
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