The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
in the parabolas equation
2 answers:
Answer:
Step-by-step explanation:
Remark
The general formula for the vertex of a parabola is
y = a(x - b) + c
What you know from the vertex is the formula describes b and c and the y intercept gives you the information to solve for a.
Solution
y = a(x - 2)^2 - 1 If you graph this, the vertex should be at (2,-1). I'll upload the graph at the end.
Now we need to solve for a
x = 0
y = 5
5 = a(0 - 2)^2 - 1
5 = a(4) - 1 Add 1 to both sides.
6 = a(4) Divide by 4
6/4 = a 4/4 Switch
a = 3/2
Answer
y = 3/2 (x - 2)^2 - 1
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