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3 years ago

The number of tomato plants Jeff planted went from 4 last year to 12 this year. Find the percent increase.

1 answer:

6 0

200%

We find the difference, then divide that by the original. 12-4/4 = 8/4 = 2
Multiply by 100 to get the percentage, = 200%

Also, adding 4 would be a 100% increase, and adding 8 is twice that, so 200%.

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What is the value of n?

vitfil [10]

9(n+7) = 18(n+1)
9n + 63 = 18n + 18
9n = 45
n = 5

answer
n = 5

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3 years ago

How can you check the reasonableness of your solution

storchak [24]

You would basically go back and trace all your steps, that's what I do. And if your answer seems reasonable then you have the right answer but if your work doesn't match the answer than you've messed up. I hope I helped if I did like my answer and comment down below thx

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4 years ago

Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th

timurjin [86]

Answer:

35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

$E(X) = \frac{10,000 +1,000}{2} \\E(X) =\$5,500$

If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

$E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56$

The percentage reduction on the claim payment is:

$P=(1-\frac{E_2(X)}{E(X)})*100 \\P=(1-\frac{3,555.56}{5,500})*100\\P=35.35\%$

There was a 35.35% reduction.

8 0

3 years ago

The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt

Sloan [31]

Answer:

B. $5\times10^{2}$

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is $1\times 10^{-4}$ meters wide.

Using an optical microscope, we can see items up to $2\times 10^{-7}$ meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}$

Using the exponent rule of quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}$

$\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}$

Therefore, the objects we can see with our eyes are $5\times10^{2}$ times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0

3 years ago

What is the domain of this function

miskamm [114]

Answer:

D = — 4 < x < 0

D = R — ( — ∞ , —4] & [0, + ∞)

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3 years ago

The number of tomato plants Jeff planted went from 4 last year to 12 this year. Find the percent increase.​

The number of tomato plants Jeff planted went from 4 last year to 12 this year. Find the percent increase.