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2 years ago

Help if yk plz and thanks

Mathematics

2 answers:

dalvyx [7]2 years ago

8 0

Answer:

Step-by-step explanation:

The expression given is f + f + f.

f + f + f = f × 3

The correct way to write an expression that is being multiplied is to put the number before it with no symbols or spaces in between them:

f + f + f =

f × 3 =

den301095 [7]2 years ago

7 0

Answer:

I am pretty sur it is 3

Step-by-step explanation:

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Simplify 6(x+y)+(x-y)

MakcuM [25]

When you have something multiplied by more than one term in parentheses, you multiply that something (in this case 6) by both terms (x and y).
6x+6y+x+y. Add like-terms. 7x+7y

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2 years ago

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Find the slope of the line that passes through points (10,2) and (3,5)

Hunter-Best [27]

Answer:

Slope = -3/7

Step-by-step explanation:

The formula for slope is y2-y1/x2-x1.

Substitute for the points.

5-2/3-10 = -3/7

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2 years ago

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What’s the combined average of Altuve’s weighted average below:

Fynjy0 [20]

Answer:

The combined average of Altuve's weighted averages is 1 for 2 or 1/2

Step-by-step explanation:

Combined Average

On Friday, Altuve had 3 out of 5 successes

On Saturday, Altuve had 2 out of 4 successes

On Friday, Altuve had 1 out of 3 successes

The total successes are 3+2+1=6

The total tries are 5+4+3=12

The combined average is:

$\displaystyle \bar x=\frac{6}{12}$

Simplifying:

$\displaystyle \bar x=\frac{1}{2}$

The combined average of Altuve's weighted averages is 1 for 2 or 1/2

7 0

3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$ is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4}$

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0

2 years ago

Write an equasion of the line in point-slope form that passes through the points (-16, 8) (4,2)

xeze [42]

You start by finding the slope : y2 - y1 / x2 - x1

2 - 8 / 4 - (-16)

- 6 / 20

m = - 3 / 10

Point slope form : y - y1 = m( x- x1 )

You can pick either of the coordinates and substitute them in

POINT SLOPE FORM EQUATION : y - 8 = -3/10 ( x + 16 )

5 0

2 years ago