Answer:
Answer is D or a
Step-by-step explanation:
Answer: no solution
Hope this helps and good luck :)
Step-by-step explanation:
Answer:
- <u>3 </u><u>and</u><u> 17</u> are required integers
Step-by-step explanation:
- Let one integer be x
- And other integer be y
x = 4y + 5
xy = 51
<u>According to </u><u>question </u><u>:</u>
➞ (4y + 5)y = 51
➞ 4y² + 5y = 51
➞ 4y² + 5y - 51 = 0
➞ 4y² + 17y - 12y - 51 = 0
➞ y (4y + 17) - 3(4y + 17) = 0
➞ (y - 3)(4y - 17) = 0
➞ y - 3 = 0
➞ <u>y = 3</u>
Hence,
➞ <u>y = 3</u>
➞ x = 4y + 5
➞ x = 4 (3) + 5
➞ x = 12 + 5
➞<u> </u><u>x = 17</u>
∴ The required integers are <u>3 and 17</u>
The answer to the question is c
Answer:
The spinner has 6 equal-sized slices, so each slice has a 1/6 probability of showing up.
I guess that we want to find the expected value in one spin:
number 1: wins $1
number 2: wins $3
number 3: wins $5
number 4: wins $7
number 5: losses $8
number 6: loses $8
The expected value can be calculated as:
Ev = ∑xₙpₙ
where xₙ is the event and pₙ is the probability.
We know that the probability for all the events is 1/6, so we have:
Ev = ($1 + $3 + $5 + $7 - $8 - $8)*(1/6) = $0
So the expected value of this game is $0, wich implies that is a fair game.
