Answer:
1 in 12 chance of landing on 3
1 in 12 chance of landing on 4
1 in 6 chance of landing on either 3 or 4
Step-by-step explanation:
12 equal sections means probability is 1 in 12 of landing on any one numbered section.
2 in 12 or 1 in 6 chance of landing on either of two numbered sections in one attempt.
Answer:
Compound interest = Rs 1,575 (Approx.)
Step-by-step explanation:
Given:
Amount invested = R.s 6,500
Rate of interest = 7.5% per annum
Number of year = 3 year
Find:
Amount of compound interest
Computation:
Compound interest = P[(1+r)ⁿ - 1]
Compound interest = 6500[(1+7.5%)³ - 1]
Compound interest = 6500[(1+0.075)³ - 1]
Compound interest = 6500[(1.075)³ - 1]
Compound interest = 6500[1.2423 - 1]
Compound interest = 6500[0.2423]
Compound interest = 1574.95
Compound interest = Rs 1,575 (Approx.)
Answer:
a) M =82
Step-by-step explanation:
Let´s study this as a Normal distribution.
As we know in a normal distribution the z score is = (X-μ)/(sd/sqrt(n))
where
X = mean for the taken sample = What we want to know in this problem
μ = Total population mean =80
sd= standard deviation= 12
n = sample size=9
So in this case z=( X-80)/(12/sqr(9))= (X-80)/4
also we know that the effect size taken by the machine is 0.5, which is the same as the z-score
so...
0.5 = (X-80)/4 => 0.5*4 = X-80
2+80 = X
X = 82
Plug into calculator...
solve(2(-y+1)-3y=-30,y)
y=6.4
