Y = x^2 + 2x - 1 = x^2 + 2x + 1 - 1 - 1 = (x + 1)^2 - 2
The vertex of a parabola given by y = a(x - h)^2 + k is (h, k).
Therefore, the vertex of y = (x + 1)^2 - 2 is (-1, -2)
Answer:
-3a-4b+5
Step-by-step explanation:
(3a-6b+12)-(6a-2b+7)
3a-6b+12-6a+2b-7
3a-6a-6b+2b+12-7
-3a-4b+5
30 + 2 = 32
Answer:
??? I have the same problem itsits hard??, help me please