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eimsori [14]
3 years ago
7

PLEASE HELP! I WILL MARK TOU AS BRAINLEIST!

Mathematics
2 answers:
san4es73 [151]3 years ago
6 0

Answer:

a.Z(-2,1)

b.Z(1,1)

c.Z(-3,2)

Step-by-step explanation:

z(-2,3)

Imagine this point on a graph.

Translate it down two units :

the x stays -2, by going down the y decreases 2 so 3-2=1

Z(-2,1)

Translate Right three units : I'm assuming that we use the answer from the first translation

Z(-2,1)

The y doesn't change this time the x increases 3 since we're moving to the right.

Z(1,1)

Translate up 1 and left 4:

Z(1,1)

by moving up one we have Z(1,2) then by moving 4 to the left we get Z(-3,2)

Hope this helps :)

juin [17]3 years ago
5 0

Given the point Z(-2, 3) I would determine the new coordinate of its image by moving down two units because if you move two units you will get the response of 1. If you move right three units  -8. If you move up one unit and left four units you get the response of 9.

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3 years ago
What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
Setler79 [48]

Answer:

k=-16,k=-8,k=8,k=16

Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

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now, we can multiply factor term

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now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

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we are given that

'a' and 'b' are integers

so, we can find all possible factors

15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

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we can plug values

k=-1-15

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At (1\times 15):

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we can plug values

k=1+15

k=16

At (-3\times -5):

k=a+b

we can plug values

k=-3-5

k=-8

At (3\times 5):

k=a+b

we can plug values

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So, values of k are

k=-16,k=-8,k=8,k=16

6 0
3 years ago
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