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3 years ago

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Practice questions for upcoming test

2 answers:

Elis [28]3 years ago

8 0

First convert 1/8 inch to millimeters.

25.4/8 = 3.175

Then find the difference.

3.175-3=0.175

I'm not 100% positive about this, but I'm pretty sure.

Hope this helps! Let me know if you need any more help by commenting or DMing me. If it helped, please rate, thank, and if it really helped, give brainliest. It helps me rank up. Thanks! :)

tino4ka555 [31]3 years ago

7 0

If one inch equals 25.4 millimeters, you would have to divide 25.4 by 1/8 which equals to 3.2 (3.175 before rounding). Subtract 3.2 from 25.4 = 22.2 millimeters

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Please solve fast. I will give Brainleist or whatever it’s called

alina1380 [7]

Answer:

84in

Step-by-step explanation:

84in

4 0

3 years ago

Help me please how to solve y=1/2x-6

Dvinal [7]

Y=(1/2)x-6 and solving for x.
So first you bring the 6 to the other side: y+6=(1/2)x
Then you divide by (1/2) to isolate the x (y+6)/(1/2)=x
This simplifies to 2(y+6)=x because dividing by one half is the same as multiplying by 2
Hope this helps :)

4 0

3 years ago

The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

so

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

Belle walks n mile each morning and 16 miles each evening.

Rom4ik [11]

This makes no since.

6 0

3 years ago

Which type of triangle is formed given the following angle measurements?

djverab [1.8K]

Answer:

equilateral

Step-by-step explanation:

all angles are the same size. Has to be equilateral

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3 years ago