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2 years ago

IN HURRY！！！！

Mathematics

1 answer:

anzhelika [568]2 years ago

5 0

Answer: For problem 8:

sin A/a sinB/b = sinC/c

so sin50/15 = sinB/12

0.766/15 =sinB/12

0.051066 = sin B/12

sin B = 0.6128

B = 37.79 degrees

sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c

.051066= 0.99925/c

c = .99925/0.051066 = 19.567

Problems 9 and 10 can also be done with the same method as problem 8.For problem 8:

sin A/a sinB/b = sinC/c

so sin50/15 = sinB/12

0.766/15 =sinB/12

0.051066 = sin B/12

sin B = 0.6128

B = 37.79 degrees

sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c

.051066= 0.99925/c

c = .99925/0.051066 = 19.567

Problems 9 and 10 can also be done with the same method as problem 8.

<em>This is not my answer. I shall give credit to the rightful owner of these answers.</em>

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